2x2+x-1/4=0

Solution for 2x2+x-1/4=0 equation:

2x^2+x-1/4=0

We multiply all the terms by the denominator


2x^2*4+x*4-1=0

Wy multiply elements

8x^2+4x-1=0

a = 8; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·8·(-1)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{3}}{2*8}=\frac{-4-4\sqrt{3}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{3}}{2*8}=\frac{-4+4\sqrt{3}}{16}
$