2x2+8x-4.5=0

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Solution for 2x2+8x-4.5=0 equation:



2x^2+8x-4.5=0
a = 2; b = 8; c = -4.5;
Δ = b2-4ac
Δ = 82-4·2·(-4.5)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-10}{2*2}=\frac{-18}{4} =-4+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+10}{2*2}=\frac{2}{4} =1/2 $

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