2x2+5x(-4x+8)=2x2-20x2+4

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Solution for 2x2+5x(-4x+8)=2x2-20x2+4 equation: 



2x^2+5x(-4x+8)=2x^2-20x^2+4

We move all terms to the left:

2x^2+5x(-4x+8)-(2x^2-20x^2+4)=0

We multiply parentheses

2x^2-(2x^2-20x^2+4)-20x^2+40x=0

We get rid of parentheses

2x^2-2x^2+20x^2-20x^2+40x-4=0

We add all the numbers together, and all the variables

40x-4=0

We move all terms containing x to the left, all other terms to the right

40x=4

x=4/40

x=1/10

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