If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+3x-1260=0
a = 2; b = 3; c = -1260;
Δ = b2-4ac
Δ = 32-4·2·(-1260)
Δ = 10089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10089}=\sqrt{9*1121}=\sqrt{9}*\sqrt{1121}=3\sqrt{1121}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{1121}}{2*2}=\frac{-3-3\sqrt{1121}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{1121}}{2*2}=\frac{-3+3\sqrt{1121}}{4} $
| 4x-7/3-13/6+2x=1/3(10x-27) | | F(x)=x3+4x-7 | | 186+x=5x | | 168+x=20x | | 1.75/x=0.75 | | L=3s+1 | | 5/3x*6=10x | | 704=2*22/7*8(8+h) | | 8.4-x-x^2=0 | | 2(1.8^x)=1000 | | 5x-(2+5x)=10 | | 130x=30 | | (2x+1)(x-1)=9 | | 50000n2+750000n=3200000 | | 6=6a-12 | | 12X-8y-108=0 | | f-35=67 | | y+125=14 | | (5x+5)(4x-5)=180 | | (x/2-x/3)=(1) | | 1/2+n=24 | | (x-3)=(4x+12) | | (x-3)=4x+12) | | (7x-(3x-5))=(6x-9) | | 3x^2+35x+7=0 | | 1.5a/3-2a/5=7.5a/15-1 | | (7x+(3x-5))=(6x-9) | | y-125=14 | | (3x+4)=5x-6) | | (2367-x)/x=0.04 | | (x-6(x+4))=(3-4(2x+5)) | | x+(x*2)+(x*1.5)=60 |