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2x^2+3=x-23
We move all terms to the left:
2x^2+3-(x-23)=0
We get rid of parentheses
2x^2-x+23+3=0
We add all the numbers together, and all the variables
2x^2-1x+26=0
a = 2; b = -1; c = +26;
Δ = b2-4ac
Δ = -12-4·2·26
Δ = -207
Delta is less than zero, so there is no solution for the equation
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