2x2+25x-45=72

Solution for 2x2+25x-45=72 equation:

2x^2+25x-45=72

We move all terms to the left:

2x^2+25x-45-(72)=0

We add all the numbers together, and all the variables

2x^2+25x-117=0

a = 2; b = 25; c = -117;
Δ = b2-4ac
Δ = 252-4·2·(-117)
Δ = 1561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1561}}{2*2}=\frac{-25-\sqrt{1561}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1561}}{2*2}=\frac{-25+\sqrt{1561}}{4}
$