2x2+22x+56=0

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Solution for 2x2+22x+56=0 equation: 



2x^2+22x+56=0

a = 2; b = 22; c = +56;
Δ = b2-4ac
Δ = 222-4·2·56
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-6}{2*2}=\frac{-28}{4}
=-7
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+6}{2*2}=\frac{-16}{4}
=-4
$

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