If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+20x+-68=0
We add all the numbers together, and all the variables
2x^2+20x=0
a = 2; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·2·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*2}=\frac{-40}{4} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*2}=\frac{0}{4} =0 $
| 3y+8=2y-6-6y | | 2(8x)=3(2x)-7 | | -20=5x-10-3x+4 | | 3+4p=-5+5p | | 18=-6+3n | | 72=-7d+9 | | x-8+7/8=-177/8 | | 2(8+x)=3(2x)-7 | | x-3/2+x+9/5=5/2 | | -6(5-4n)=162 | | -10-8g=-g-10g+8 | | 28=5(y+6)-3y | | 3.7-2.8x=3.7 | | x-4+2/3=1/3 | | -5v+2(v+3)=-3 | | 5x+1=-11-x | | n*721=721 | | -2(3y-7)-y=-3(y-5) | | 5-2(3x-3=29 | | 16=7-2x-5x | | 6-3(4x-7)-3=0 | | 5y=35+10× | | 7x+4=3x+28. | | 135=3(7x-5)+3 | | b+(3-)=-9 | | 8y7=9 | | |x|=−100 | | 12x+7=-77 | | x+7/9=140 | | 2x+6=3x−12x+6=3x−1 | | -2x+9=-6x+1 | | .2x+6=3x−12x+6=3x−1 |