2x2+17x+24=0

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Solution for 2x2+17x+24=0 equation: 



2x^2+17x+24=0

a = 2; b = 17; c = +24;
Δ = b2-4ac
Δ = 172-4·2·24
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{97}}{2*2}=\frac{-17-\sqrt{97}}{4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{97}}{2*2}=\frac{-17+\sqrt{97}}{4}
$

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