2x2+16x=66

Solution for 2x2+16x=66 equation:

2x^2+16x=66

We move all terms to the left:

2x^2+16x-(66)=0

a = 2; b = 16; c = -66;
Δ = b2-4ac
Δ = 162-4·2·(-66)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-28}{2*2}=\frac{-44}{4}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+28}{2*2}=\frac{12}{4}
=3
$