If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+12x-32=0
a = 2; b = 12; c = -32;
Δ = b2-4ac
Δ = 122-4·2·(-32)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-20}{2*2}=\frac{-32}{4} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+20}{2*2}=\frac{8}{4} =2 $
| (x=-10) | | -2(6-6.5n)=18.5 | | 6x2+7x-5=0 | | X2+9x+8=48 | | ((2x-1)/4)=5x+1 | | 5x=3x+62 | | (3a)-11=10 | | x-4=120+x=-32 | | h–7/2 = 1 | | a^2+a^2=15.75 | | 8=v/10.24 | | -11x-5x=18 | | 20+(2a)=52 | | 1-x-5/9=9+x | | 6(x+1)-2(x-3)=14 | | 2(x-5)=10+x | | 6.5z+2-5=30.5 | | 3x+3/4=12 | | 3.4+5z=6.9 | | 1+(18-7a)=-9 | | –7.4x=–22.2(x=3 | | (2+x)^2-(2x-4)^2+4x-2=2^2+x^2+2*2*x | | x^2+10=2x^2-3x | | 4(5)−3y=18 | | 2+1.25f=10-2.7(f | | -9(3d+2)=16.5 | | 2/3x+1/2x=21 | | 44.79-2p=123.98 | | 5x^2+20x+65=0 | | 2x+3=3(x+1)-x | | 12-(8a)=-1 | | −2x2=4x−16 |