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2x^2+10=4-4x
We move all terms to the left:
2x^2+10-(4-4x)=0
We add all the numbers together, and all the variables
2x^2-(-4x+4)+10=0
We get rid of parentheses
2x^2+4x-4+10=0
We add all the numbers together, and all the variables
2x^2+4x+6=0
a = 2; b = 4; c = +6;
Δ = b2-4ac
Δ = 42-4·2·6
Δ = -32
Delta is less than zero, so there is no solution for the equation
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