2x/7=2+(4x/3)

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Solution for 2x/7=2+(4x/3) equation: 



2x/7=2+(4x/3)

We move all terms to the left:

2x/7-(2+(4x/3))=0

We add all the numbers together, and all the variables

2x/7-(2+(+4x/3))=0

We calculate fractions


6x^2/()+(-(2+(+4x*7)/()=0



We calculate terms in parentheses: +(-(2+(+4x*7)/(), so:

-(2+(+4x*7)/(

We multiply all the terms by the denominator


-(2+(+4x*7)



We calculate terms in parentheses: -(2+(+4x*7), so:

2+(+4x*7

determiningTheFunctionDomain
(+4x*7+2

Back to the equation:

-((+4x*7+2)



We add all the numbers together, and all the variables

-((4x*7+2)



We calculate terms in parentheses: -((4x*7+2), so:

(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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(4x*7+2





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