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2x/5x+2x=2/7
We move all terms to the left:
2x/5x+2x-(2/7)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2x/5x+2x-(+2/7)=0
We add all the numbers together, and all the variables
2x+2x/5x-(+2/7)=0
We get rid of parentheses
2x+2x/5x-2/7=0
We calculate fractions
2x+14x/35x+(-10x)/35x=0
We multiply all the terms by the denominator
2x*35x+14x+(-10x)=0
We add all the numbers together, and all the variables
14x+2x*35x+(-10x)=0
Wy multiply elements
70x^2+14x+(-10x)=0
We get rid of parentheses
70x^2+14x-10x=0
We add all the numbers together, and all the variables
70x^2+4x=0
a = 70; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·70·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*70}=\frac{-8}{140} =-2/35 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*70}=\frac{0}{140} =0 $
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