2x/5=4(x-1)/9

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Solution for 2x/5=4(x-1)/9 equation: 



2x/5=4(x-1)/9

We move all terms to the left:

2x/5-(4(x-1)/9)=0

We calculate fractions


18x^2/()+(-(4(x-1)*5)/()=0



We calculate terms in parentheses: +(-(4(x-1)*5)/(), so:

-(4(x-1)*5)/(

We multiply all the terms by the denominator


-(4(x-1)*5)



We calculate terms in parentheses: -(4(x-1)*5), so:

4(x-1)*5

We multiply parentheses

20x-20

Back to the equation:

-(20x-20)



We get rid of parentheses

-20x+20

Back to the equation:

+(-20x+20)



We get rid of parentheses

18x^2/()-20x+20=0

We multiply all the terms by the denominator


18x^2-20x*()+20*()=0

We add all the numbers together, and all the variables

18x^2-20x*()=0

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