2x/5=(x-1)/3

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Solution for 2x/5=(x-1)/3 equation: 



2x/5=(x-1)/3

We move all terms to the left:

2x/5-((x-1)/3)=0

We calculate fractions


6x^2/()+(-((x-1)*5)/()=0



We calculate terms in parentheses: +(-((x-1)*5)/(), so:

-((x-1)*5)/(

We multiply all the terms by the denominator


-((x-1)*5)



We calculate terms in parentheses: -((x-1)*5), so:

(x-1)*5

We multiply parentheses

5x-5

Back to the equation:

-(5x-5)



We get rid of parentheses

-5x+5

Back to the equation:

+(-5x+5)



We get rid of parentheses

6x^2/()-5x+5=0

We multiply all the terms by the denominator


6x^2-5x*()+5*()=0

We add all the numbers together, and all the variables

6x^2-5x*()=0

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