2x/5=(x+2)/2

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Solution for 2x/5=(x+2)/2 equation: 



2x/5=(x+2)/2

We move all terms to the left:

2x/5-((x+2)/2)=0

We calculate fractions


4x^2/()+(-((x+2)*5)/()=0



We calculate terms in parentheses: +(-((x+2)*5)/(), so:

-((x+2)*5)/(

We multiply all the terms by the denominator


-((x+2)*5)



We calculate terms in parentheses: -((x+2)*5), so:

(x+2)*5

We multiply parentheses

5x+10

Back to the equation:

-(5x+10)



We get rid of parentheses

-5x-10

Back to the equation:

+(-5x-10)



We get rid of parentheses

4x^2/()-5x-10=0

We multiply all the terms by the denominator


4x^2-5x*()-10*()=0

We add all the numbers together, and all the variables

4x^2-5x*()=0

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