2x/3=-24/x

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Solution for 2x/3=-24/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x)/3 = -24/x // + -24/x

(2*x)/3-(-24/x) = 0

(2*x)/3+24*x^-1 = 0

2/3*x^1+24*x^-1 = 0

(2/3*x^2+24*x^0)/(x^1) = 0 // * x^2

x^1*(2/3*x^2+24*x^0) = 0

x^1

(2/3)*x^2+24 = 0

(2/3)*x^2+24 = 0

DELTA = 0^2-(4*24*(2/3))

DELTA = -64

DELTA < 0

x in { } 

x belongs to the empty set

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