2x/3=(x+1)/4

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Solution for 2x/3=(x+1)/4 equation: 



2x/3=(x+1)/4

We move all terms to the left:

2x/3-((x+1)/4)=0

We calculate fractions


8x^2/()+(-((x+1)*3)/()=0



We calculate terms in parentheses: +(-((x+1)*3)/(), so:

-((x+1)*3)/(

We multiply all the terms by the denominator


-((x+1)*3)



We calculate terms in parentheses: -((x+1)*3), so:

(x+1)*3

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

-3x-3

Back to the equation:

+(-3x-3)



We get rid of parentheses

8x^2/()-3x-3=0

We multiply all the terms by the denominator


8x^2-3x*()-3*()=0

We add all the numbers together, and all the variables

8x^2-3x*()=0

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