2x-9/3x+8=3/7x

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Solution for 2x-9/3x+8=3/7x equation: 



2x-9/3x+8=3/7x

We move all terms to the left:

2x-9/3x+8-(3/7x)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2x-9/3x-(+3/7x)+8=0

We get rid of parentheses

2x-9/3x-3/7x+8=0

We calculate fractions


2x+(-63x)/21x^2+(-9x)/21x^2+8=0

We multiply all the terms by the denominator


2x*21x^2+(-63x)+(-9x)+8*21x^2=0

Wy multiply elements

42x^3+168x^2+(-63x)+(-9x)=0

We get rid of parentheses

42x^3+168x^2-63x-9x=0

We do not support expression: x^3

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