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2x-8/x+5=4
We move all terms to the left:
2x-8/x+5-(4)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
2x-8/x+1=0
We multiply all the terms by the denominator
2x*x+1*x-8=0
We add all the numbers together, and all the variables
x+2x*x-8=0
Wy multiply elements
2x^2+x-8=0
a = 2; b = 1; c = -8;
Δ = b2-4ac
Δ = 12-4·2·(-8)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{65}}{2*2}=\frac{-1-\sqrt{65}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{65}}{2*2}=\frac{-1+\sqrt{65}}{4} $
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