2x-8-5(3x-7)=-3(x+1)

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Solution for 2x-8-5(3x-7)=-3(x+1) equation: 



2x-8-5(3x-7)=-3(x+1)

We move all terms to the left:

2x-8-5(3x-7)-(-3(x+1))=0

We multiply parentheses

2x-15x-(-3(x+1))+35-8=0



We calculate terms in parentheses: -(-3(x+1)), so:

-3(x+1)

We multiply parentheses

-3x-3

Back to the equation:

-(-3x-3)



We add all the numbers together, and all the variables

-13x-(-3x-3)+27=0

We get rid of parentheses

-13x+3x+3+27=0

We add all the numbers together, and all the variables

-10x+30=0

We move all terms containing x to the left, all other terms to the right

-10x=-30

x=-30/-10

x=+3

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