2x-7=8/x-3

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Solution for 2x-7=8/x-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-7 = 8/x-3 // - 8/x-3

2*x-(8/x)-7+3 = 0

2*x-8*x^-1-7+3 = 0

2*x^1-8*x^-1-4*x^0 = 0

(2*x^2-4*x^1-8*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-4*x^1-8*x^0) = 0

x^1

2*x^2-4*x-8 = 0

2*x^2-4*x-8 = 0

DELTA = (-4)^2-(-8*2*4)

DELTA = 80

DELTA > 0

x = (80^(1/2)+4)/(2*2) or x = (4-80^(1/2))/(2*2)

x = (4*5^(1/2)+4)/4 or x = (4-4*5^(1/2))/4

x in { (4-4*5^(1/2))/4, (4*5^(1/2)+4)/4} 

x in { (4-4*5^(1/2))/4, (4*5^(1/2)+4)/4 }

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