2x-7=-3(x-1)2x-7=3(x-1)

Solution for 2x-7=-3(x-1)2x-7=3(x-1) equation:

2x-7=-3(x-1)2x-7=3(x-1)

We move all terms to the left:

2x-7-(-3(x-1)2x-7)=0


We calculate terms in parentheses: -(-3(x-1)2x-7), so:

-3(x-1)2x-7

We multiply parentheses

-6x^2+6x-7

Back to the equation:

-(-6x^2+6x-7)


We get rid of parentheses

6x^2-6x+2x+7-7=0

We add all the numbers together, and all the variables

6x^2-4x=0

a = 6; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·6·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*6}=\frac{8}{12}
=2/3
$