2x-6+7x=3(6x-4)+3

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Solution for 2x-6+7x=3(6x-4)+3 equation: 



2x-6+7x=3(6x-4)+3

We move all terms to the left:

2x-6+7x-(3(6x-4)+3)=0

We add all the numbers together, and all the variables

9x-(3(6x-4)+3)-6=0



We calculate terms in parentheses: -(3(6x-4)+3), so:

3(6x-4)+3

We multiply parentheses

18x-12+3

We add all the numbers together, and all the variables

18x-9

Back to the equation:

-(18x-9)



We get rid of parentheses

9x-18x+9-6=0

We add all the numbers together, and all the variables

-9x+3=0

We move all terms containing x to the left, all other terms to the right

-9x=-3

x=-3/-9

x=1/3

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