2x-6+3x=2(-2x+2)+18

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Solution for 2x-6+3x=2(-2x+2)+18 equation: 



2x-6+3x=2(-2x+2)+18

We move all terms to the left:

2x-6+3x-(2(-2x+2)+18)=0

We add all the numbers together, and all the variables

5x-(2(-2x+2)+18)-6=0



We calculate terms in parentheses: -(2(-2x+2)+18), so:

2(-2x+2)+18

We multiply parentheses

-4x+4+18

We add all the numbers together, and all the variables

-4x+22

Back to the equation:

-(-4x+22)



We get rid of parentheses

5x+4x-22-6=0

We add all the numbers together, and all the variables

9x-28=0

We move all terms containing x to the left, all other terms to the right

9x=28

x=28/9

x=3+1/9

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