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2x-5x(x-4)=-2+5x-2
We move all terms to the left:
2x-5x(x-4)-(-2+5x-2)=0
We add all the numbers together, and all the variables
2x-5x(x-4)-(5x-4)=0
We multiply parentheses
-5x^2+2x+20x-(5x-4)=0
We get rid of parentheses
-5x^2+2x+20x-5x+4=0
We add all the numbers together, and all the variables
-5x^2+17x+4=0
a = -5; b = 17; c = +4;
Δ = b2-4ac
Δ = 172-4·(-5)·4
Δ = 369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{369}=\sqrt{9*41}=\sqrt{9}*\sqrt{41}=3\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-3\sqrt{41}}{2*-5}=\frac{-17-3\sqrt{41}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+3\sqrt{41}}{2*-5}=\frac{-17+3\sqrt{41}}{-10} $
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