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2x-5+3x=5x-(x-4)+2
We move all terms to the left:
2x-5+3x-(5x-(x-4)+2)=0
We add all the numbers together, and all the variables
5x-(5x-(x-4)+2)-5=0
We calculate terms in parentheses: -(5x-(x-4)+2), so:We get rid of parentheses
5x-(x-4)+2
We get rid of parentheses
5x-x+4+2
We add all the numbers together, and all the variables
4x+6
Back to the equation:
-(4x+6)
5x-4x-6-5=0
We add all the numbers together, and all the variables
x-11=0
We move all terms containing x to the left, all other terms to the right
x=11
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