2x-5(x-4)=8+4x-28

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Solution for 2x-5(x-4)=8+4x-28 equation: 



2x-5(x-4)=8+4x-28

We move all terms to the left:

2x-5(x-4)-(8+4x-28)=0

We add all the numbers together, and all the variables

2x-5(x-4)-(4x-20)=0

We multiply parentheses

2x-5x-(4x-20)+20=0

We get rid of parentheses

2x-5x-4x+20+20=0

We add all the numbers together, and all the variables

-7x+40=0

We move all terms containing x to the left, all other terms to the right

-7x=-40

x=-40/-7

x=5+5/7

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