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2x-5(x-3)=9(x-10)
We move all terms to the left:
2x-5(x-3)-(9(x-10))=0
We multiply parentheses
2x-5x-(9(x-10))+15=0
We calculate terms in parentheses: -(9(x-10)), so:We add all the numbers together, and all the variables
9(x-10)
We multiply parentheses
9x-90
Back to the equation:
-(9x-90)
-3x-(9x-90)+15=0
We get rid of parentheses
-3x-9x+90+15=0
We add all the numbers together, and all the variables
-12x+105=0
We move all terms containing x to the left, all other terms to the right
-12x=-105
x=-105/-12
x=8+3/4
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