2x-5(2-x)=(x-3)+2x+1

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Solution for 2x-5(2-x)=(x-3)+2x+1 equation: 



2x-5(2-x)=(x-3)+2x+1

We move all terms to the left:

2x-5(2-x)-((x-3)+2x+1)=0

We add all the numbers together, and all the variables

2x-5(-1x+2)-((x-3)+2x+1)=0

We multiply parentheses

2x+5x-((x-3)+2x+1)-10=0



We calculate terms in parentheses: -((x-3)+2x+1), so:

(x-3)+2x+1

We add all the numbers together, and all the variables

2x+(x-3)+1

We get rid of parentheses

2x+x-3+1

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

7x-(3x-2)-10=0

We get rid of parentheses

7x-3x+2-10=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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