2x-4x(x-5)=-2+5x=27

Solution for 2x-4x(x-5)=-2+5x=27 equation:

2x-4x(x-5)=-2+5x=27

We move all terms to the left:

2x-4x(x-5)-(-2+5x)=0

We add all the numbers together, and all the variables

2x-4x(x-5)-(5x-2)=0

We multiply parentheses

-4x^2+2x+20x-(5x-2)=0

We get rid of parentheses

-4x^2+2x+20x-5x+2=0

We add all the numbers together, and all the variables

-4x^2+17x+2=0

a = -4; b = 17; c = +2;
Δ = b2-4ac
Δ = 172-4·(-4)·2
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{321}}{2*-4}=\frac{-17-\sqrt{321}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{321}}{2*-4}=\frac{-17+\sqrt{321}}{-8}
$