2x-4+6x=2(4x-2)

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Solution for 2x-4+6x=2(4x-2) equation: 



2x-4+6x=2(4x-2)

We move all terms to the left:

2x-4+6x-(2(4x-2))=0

We add all the numbers together, and all the variables

8x-(2(4x-2))-4=0



We calculate terms in parentheses: -(2(4x-2)), so:

2(4x-2)

We multiply parentheses

8x-4

Back to the equation:

-(8x-4)



We get rid of parentheses

8x-8x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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