2x-4+3(5-x)=5(2x-1)+3(2x+5)-8x

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Solution for 2x-4+3(5-x)=5(2x-1)+3(2x+5)-8x equation: 



2x-4+3(5-x)=5(2x-1)+3(2x+5)-8x

We move all terms to the left:

2x-4+3(5-x)-(5(2x-1)+3(2x+5)-8x)=0

We add all the numbers together, and all the variables

2x+3(-1x+5)-(5(2x-1)+3(2x+5)-8x)-4=0

We multiply parentheses

2x-3x-(5(2x-1)+3(2x+5)-8x)+15-4=0



We calculate terms in parentheses: -(5(2x-1)+3(2x+5)-8x), so:

5(2x-1)+3(2x+5)-8x

We add all the numbers together, and all the variables

-8x+5(2x-1)+3(2x+5)

We multiply parentheses

-8x+10x+6x-5+15

We add all the numbers together, and all the variables

8x+10

Back to the equation:

-(8x+10)



We add all the numbers together, and all the variables

-1x-(8x+10)+11=0

We get rid of parentheses

-1x-8x-10+11=0

We add all the numbers together, and all the variables

-9x+1=0

We move all terms containing x to the left, all other terms to the right

-9x=-1

x=-1/-9

x=1/9

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