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2x-4(x-5)=-3+2x+11
We move all terms to the left:
2x-4(x-5)-(-3+2x+11)=0
We add all the numbers together, and all the variables
2x-4(x-5)-(2x+8)=0
We multiply parentheses
2x-4x-(2x+8)+20=0
We get rid of parentheses
2x-4x-2x-8+20=0
We add all the numbers together, and all the variables
-4x+12=0
We move all terms containing x to the left, all other terms to the right
-4x=-12
x=-12/-4
x=+3
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