2x-4(x-4)=-8+5x+3

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Solution for 2x-4(x-4)=-8+5x+3 equation: 



2x-4(x-4)=-8+5x+3

We move all terms to the left:

2x-4(x-4)-(-8+5x+3)=0

We add all the numbers together, and all the variables

2x-4(x-4)-(5x-5)=0

We multiply parentheses

2x-4x-(5x-5)+16=0

We get rid of parentheses

2x-4x-5x+5+16=0

We add all the numbers together, and all the variables

-7x+21=0

We move all terms containing x to the left, all other terms to the right

-7x=-21

x=-21/-7

x=+3

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