2x-4(x-3)=-8+3x-10

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Solution for 2x-4(x-3)=-8+3x-10 equation: 



2x-4(x-3)=-8+3x-10

We move all terms to the left:

2x-4(x-3)-(-8+3x-10)=0

We add all the numbers together, and all the variables

2x-4(x-3)-(3x-18)=0

We multiply parentheses

2x-4x-(3x-18)+12=0

We get rid of parentheses

2x-4x-3x+18+12=0

We add all the numbers together, and all the variables

-5x+30=0

We move all terms containing x to the left, all other terms to the right

-5x=-30

x=-30/-5

x=+6

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