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2x-4(x-3)=-7+2x+11
We move all terms to the left:
2x-4(x-3)-(-7+2x+11)=0
We add all the numbers together, and all the variables
2x-4(x-3)-(2x+4)=0
We multiply parentheses
2x-4x-(2x+4)+12=0
We get rid of parentheses
2x-4x-2x-4+12=0
We add all the numbers together, and all the variables
-4x+8=0
We move all terms containing x to the left, all other terms to the right
-4x=-8
x=-8/-4
x=+2
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