2x-4(x-2)=8+5x-40

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Solution for 2x-4(x-2)=8+5x-40 equation: 



2x-4(x-2)=8+5x-40

We move all terms to the left:

2x-4(x-2)-(8+5x-40)=0

We add all the numbers together, and all the variables

2x-4(x-2)-(5x-32)=0

We multiply parentheses

2x-4x-(5x-32)+8=0

We get rid of parentheses

2x-4x-5x+32+8=0

We add all the numbers together, and all the variables

-7x+40=0

We move all terms containing x to the left, all other terms to the right

-7x=-40

x=-40/-7

x=5+5/7

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