2x-4(3+2x)+8=10x-4

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Solution for 2x-4(3+2x)+8=10x-4 equation: 



2x-4(3+2x)+8=10x-4

We move all terms to the left:

2x-4(3+2x)+8-(10x-4)=0

We add all the numbers together, and all the variables

2x-4(2x+3)-(10x-4)+8=0

We multiply parentheses

2x-8x-(10x-4)-12+8=0

We get rid of parentheses

2x-8x-10x+4-12+8=0

We add all the numbers together, and all the variables

-16x=0

x=0/-16

x=0

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