2x-4(2-3x)=5(x-4)-33

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Solution for 2x-4(2-3x)=5(x-4)-33 equation: 



2x-4(2-3x)=5(x-4)-33

We move all terms to the left:

2x-4(2-3x)-(5(x-4)-33)=0

We add all the numbers together, and all the variables

2x-4(-3x+2)-(5(x-4)-33)=0

We multiply parentheses

2x+12x-(5(x-4)-33)-8=0



We calculate terms in parentheses: -(5(x-4)-33), so:

5(x-4)-33

We multiply parentheses

5x-20-33

We add all the numbers together, and all the variables

5x-53

Back to the equation:

-(5x-53)



We add all the numbers together, and all the variables

14x-(5x-53)-8=0

We get rid of parentheses

14x-5x+53-8=0

We add all the numbers together, and all the variables

9x+45=0

We move all terms containing x to the left, all other terms to the right

9x=-45

x=-45/9

x=-5

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