2x-4(2-3x)=5(x-3)-47

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Solution for 2x-4(2-3x)=5(x-3)-47 equation: 



2x-4(2-3x)=5(x-3)-47

We move all terms to the left:

2x-4(2-3x)-(5(x-3)-47)=0

We add all the numbers together, and all the variables

2x-4(-3x+2)-(5(x-3)-47)=0

We multiply parentheses

2x+12x-(5(x-3)-47)-8=0



We calculate terms in parentheses: -(5(x-3)-47), so:

5(x-3)-47

We multiply parentheses

5x-15-47

We add all the numbers together, and all the variables

5x-62

Back to the equation:

-(5x-62)



We add all the numbers together, and all the variables

14x-(5x-62)-8=0

We get rid of parentheses

14x-5x+62-8=0

We add all the numbers together, and all the variables

9x+54=0

We move all terms containing x to the left, all other terms to the right

9x=-54

x=-54/9

x=-6

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