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2x-3x(6x-11)=-7
We move all terms to the left:
2x-3x(6x-11)-(-7)=0
We add all the numbers together, and all the variables
2x-3x(6x-11)+7=0
We multiply parentheses
-18x^2+2x+33x+7=0
We add all the numbers together, and all the variables
-18x^2+35x+7=0
a = -18; b = 35; c = +7;
Δ = b2-4ac
Δ = 352-4·(-18)·7
Δ = 1729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1729}}{2*-18}=\frac{-35-\sqrt{1729}}{-36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1729}}{2*-18}=\frac{-35+\sqrt{1729}}{-36} $
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