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2x-3=5(x/4)+1
We move all terms to the left:
2x-3-(5(x/4)+1)=0
We add all the numbers together, and all the variables
2x-(5(+x/4)+1)-3=0
We multiply all the terms by the denominator
2x*4)+1)-(5(+x-3*4)+1)=0
We add all the numbers together, and all the variables
2x*4)+1)-(5(x-12)+1)=0
We add all the numbers together, and all the variables
2x*4)+1)-(5(x=0
Wy multiply elements
8x^2=0
a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{16}=0$
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