2x-3/x-1=8x+1/4x+5

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Solution for 2x-3/x-1=8x+1/4x+5 equation:



2x-3/x-1=8x+1/4x+5
We move all terms to the left:
2x-3/x-1-(8x+1/4x+5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 4x+5)!=0
x∈R
We get rid of parentheses
2x-3/x-8x-1/4x-5-1=0
We calculate fractions
2x-8x+(-12x)/4x^2+(-x)/4x^2-5-1=0
We add all the numbers together, and all the variables
2x-8x+(-12x)/4x^2+(-1x)/4x^2-5-1=0
We add all the numbers together, and all the variables
-6x+(-12x)/4x^2+(-1x)/4x^2-6=0
We multiply all the terms by the denominator
-6x*4x^2+(-12x)+(-1x)-6*4x^2=0
Wy multiply elements
-24x^3-24x^2+(-12x)+(-1x)=0
We get rid of parentheses
-24x^3-24x^2-12x-1x=0
We do not support expression: x^3

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