2x-3/x-1)=(8x+1/4x+5

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Solution for 2x-3/x-1)=(8x+1/4x+5 equation:



2x-3/x-1)=(8x+1/4x+5
We move all terms to the left:
2x-3/x-1)-((8x+1/4x+5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 4x+5)!=0
x∈R
We calculate fractions
2x+(-12x)/4x^2-((8x+1*x)/4x^2+(-1)=0
We calculate terms in parentheses: -((8x+1*x)/4x^2+(-1), so:
(8x+1*x)/4x^2+(-1
We add all the numbers together, and all the variables
(+9x)/4x^2+(-1
We add all the numbers together, and all the variables
(+9x)/4x^2
We multiply all the terms by the denominator
(+9x)
We get rid of parentheses
9x
Back to the equation:
-(9x)
We add all the numbers together, and all the variables
-7x+(-12x)/4x^2=0
We multiply all the terms by the denominator
-7x*4x^2+(-12x)=0
Wy multiply elements
-28x^3+(-12x)=0
We get rid of parentheses
-28x^3-12x=0
We do not support expression: x^3

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