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2x-3/4x=9
We move all terms to the left:
2x-3/4x-(9)=0
Domain of the equation: 4x!=0We multiply all the terms by the denominator
x!=0/4
x!=0
x∈R
2x*4x-9*4x-3=0
Wy multiply elements
8x^2-36x-3=0
a = 8; b = -36; c = -3;
Δ = b2-4ac
Δ = -362-4·8·(-3)
Δ = 1392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1392}=\sqrt{16*87}=\sqrt{16}*\sqrt{87}=4\sqrt{87}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{87}}{2*8}=\frac{36-4\sqrt{87}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{87}}{2*8}=\frac{36+4\sqrt{87}}{16} $
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