2x-3+2+4x=4x+3-2(2-x)

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Solution for 2x-3+2+4x=4x+3-2(2-x) equation: 



2x-3+2+4x=4x+3-2(2-x)

We move all terms to the left:

2x-3+2+4x-(4x+3-2(2-x))=0

We add all the numbers together, and all the variables

2x+4x-(4x+3-2(-1x+2))-3+2=0

We add all the numbers together, and all the variables

6x-(4x+3-2(-1x+2))-1=0



We calculate terms in parentheses: -(4x+3-2(-1x+2)), so:

4x+3-2(-1x+2)

determiningTheFunctionDomain
4x-2(-1x+2)+3

We multiply parentheses

4x+2x-4+3

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We get rid of parentheses

6x-6x+1-1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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