2x-3+2(3x+5)=-4(x+2)

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Solution for 2x-3+2(3x+5)=-4(x+2) equation: 



2x-3+2(3x+5)=-4(x+2)

We move all terms to the left:

2x-3+2(3x+5)-(-4(x+2))=0

We multiply parentheses

2x+6x-(-4(x+2))+10-3=0



We calculate terms in parentheses: -(-4(x+2)), so:

-4(x+2)

We multiply parentheses

-4x-8

Back to the equation:

-(-4x-8)



We add all the numbers together, and all the variables

8x-(-4x-8)+7=0

We get rid of parentheses

8x+4x+8+7=0

We add all the numbers together, and all the variables

12x+15=0

We move all terms containing x to the left, all other terms to the right

12x=-15

x=-15/12

x=-1+1/4

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