2x-3(x+2)=6-(x-1)

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Solution for 2x-3(x+2)=6-(x-1) equation: 



2x-3(x+2)=6-(x-1)

We move all terms to the left:

2x-3(x+2)-(6-(x-1))=0

We multiply parentheses

2x-3x-(6-(x-1))-6=0



We calculate terms in parentheses: -(6-(x-1)), so:

6-(x-1)

determiningTheFunctionDomain
-(x-1)+6

We get rid of parentheses

-x+1+6

We add all the numbers together, and all the variables

-1x+7

Back to the equation:

-(-1x+7)



We add all the numbers together, and all the variables

-1x-(-1x+7)-6=0

We get rid of parentheses

-1x+1x-7-6=0

We add all the numbers together, and all the variables

-13!=0

There is no solution for this equation

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